Every second, the sun provides the Earth with a radiant energy of 1.75×1017J1.75 \times 10^{17} \rm J (huge value!), so if we covered the top of the atmosphere with solar panels, we'd harvest a radiant power of 1.75×1017W1.75 \times 10^{17} \rm W. Knowing that the Earth's radius is RT≃6400kmR_T \simeq 6400 \rm km:
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